Base | Representation |
---|---|
bin | 111000111010011110… |
… | …0111011000111100011 |
3 | 102200110210202212201102 |
4 | 1301310330323013203 |
5 | 4000302112242011 |
6 | 132051520425015 |
7 | 11554520106344 |
oct | 1616474730743 |
9 | 380423685642 |
10 | 122221212131 |
11 | 47919762727 |
12 | 1b82b77816b |
13 | b6aa434a85 |
14 | 5cb63460cb |
15 | 32a4eb273b |
hex | 1c74f3b1e3 |
122221212131 has 2 divisors, whose sum is σ = 122221212132. Its totient is φ = 122221212130.
The previous prime is 122221212107. The next prime is 122221212187. The reversal of 122221212131 is 131212122221.
It is a weak prime.
It is an emirp because it is prime and its reverse (131212122221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122221212131 - 218 = 122220949987 is a prime.
It is a super-2 number, since 2×1222212121312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (122221212101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61110606065 + 61110606066.
It is an arithmetic number, because the mean of its divisors is an integer number (61110606066).
Almost surely, 2122221212131 is an apocalyptic number.
122221212131 is a deficient number, since it is larger than the sum of its proper divisors (1).
122221212131 is an equidigital number, since it uses as much as digits as its factorization.
122221212131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 192, while the sum is 20.
Adding to 122221212131 its reverse (131212122221), we get a palindrome (253433334352).
The spelling of 122221212131 in words is "one hundred twenty-two billion, two hundred twenty-one million, two hundred twelve thousand, one hundred thirty-one".
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