122222012101121 has 4 divisors (see below), whose sum is σ = 122676369023700. Its totient is φ = 121767655178544.

The previous prime is 122222012101109. The next prime is 122222012101159. The reversal of 122222012101121 is 121101210222221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 62942960995600 + 59279051105521 = 7933660^2 + 7699289^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-122222012101121 is a prime.

It is a super-3 number, since 3×122222012101121³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 122222012101093 and 122222012101102.

It is not an unprimeable number, because it can be changed into a prime (122222012104121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 227178460886 + ... + 227178461423.

It is an arithmetic number, because the mean of its divisors is an integer number (30669092255925).

Almost surely, 2^{122222012101121} is an apocalyptic number.

It is an amenable number.

122222012101121 is a deficient number, since it is larger than the sum of its proper divisors (454356922579).

122222012101121 is an equidigital number, since it uses as much as digits as its factorization.

122222012101121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 454356922578.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 122222012101121 its reverse (121101210222221), we get a palindrome (243323222323342).

The spelling of 122222012101121 in words is "one hundred twenty-two trillion, two hundred twenty-two billion, twelve million, one hundred one thousand, one hundred twenty-one".