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122222100433 is a prime number
BaseRepresentation
bin111000111010100000…
…0010011111111010001
3102200110212110000020111
41301311000103333101
54000302324203213
6132051551441321
711554530466216
oct1616500237721
9380425400214
10122222100433
114791a20a064
121b82bb26241
13b6aa6861b4
145cb64d7b0d
1532a50daa3d
hex1c75013fd1

122222100433 has 2 divisors, whose sum is σ = 122222100434. Its totient is φ = 122222100432.

The previous prime is 122222100421. The next prime is 122222100463. The reversal of 122222100433 is 334001222221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109685491344 + 12536609089 = 331188^2 + 111967^2 .

It is a cyclic number.

It is not a de Polignac number, because 122222100433 - 25 = 122222100401 is a prime.

It is not a weakly prime, because it can be changed into another prime (122222100463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61111050216 + 61111050217.

It is an arithmetic number, because the mean of its divisors is an integer number (61111050217).

Almost surely, 2122222100433 is an apocalyptic number.

It is an amenable number.

122222100433 is a deficient number, since it is larger than the sum of its proper divisors (1).

122222100433 is an equidigital number, since it uses as much as digits as its factorization.

122222100433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 122222100433 its reverse (334001222221), we get a palindrome (456223322654).

The spelling of 122222100433 in words is "one hundred twenty-two billion, two hundred twenty-two million, one hundred thousand, four hundred thirty-three".