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122230100121 = 340743366707
BaseRepresentation
bin111000111010101111…
…0110101000010011001
3102200111102111102202020
41301311132311002121
54000311401200441
6132052435125053
711554655465013
oct1616536650231
9380442442666
10122230100121
1147923783378
121b832743789
13b6ac22743c
145cb75bb1b3
1532a5b6ae66
hex1c757b5099

122230100121 has 4 divisors (see below), whose sum is σ = 162973466832. Its totient is φ = 81486733412.

The previous prime is 122230100119. The next prime is 122230100129. The reversal of 122230100121 is 121001032221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 122230100121 - 21 = 122230100119 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 122230100121.

It is not an unprimeable number, because it can be changed into a prime (122230100129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20371683351 + ... + 20371683356.

It is an arithmetic number, because the mean of its divisors is an integer number (40743366708).

Almost surely, 2122230100121 is an apocalyptic number.

It is an amenable number.

122230100121 is a deficient number, since it is larger than the sum of its proper divisors (40743366711).

122230100121 is an equidigital number, since it uses as much as digits as its factorization.

122230100121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40743366710.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 122230100121 its reverse (121001032221), we get a palindrome (243231132342).

The spelling of 122230100121 in words is "one hundred twenty-two billion, two hundred thirty million, one hundred thousand, one hundred twenty-one".

Divisors: 1 3 40743366707 122230100121