Base | Representation |
---|---|
bin | 10001110010010110111… |
… | …100010110000001110011 |
3 | 11022211222101221122202221 |
4 | 101302112330112001303 |
5 | 130011234044111311 |
6 | 2333303541421511 |
7 | 154210545016036 |
oct | 21622674260163 |
9 | 4284871848687 |
10 | 1222303113331 |
11 | 431415273263 |
12 | 178a82a0a897 |
13 | 8b3551878a1 |
14 | 4323464d01d |
15 | 21bdcc40671 |
hex | 11c96f16073 |
1222303113331 has 2 divisors, whose sum is σ = 1222303113332. Its totient is φ = 1222303113330.
The previous prime is 1222303113319. The next prime is 1222303113347. The reversal of 1222303113331 is 1333113032221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1222303113331 - 213 = 1222303105139 is a prime.
It is a super-2 number, since 2×12223031133312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1222303113296 and 1222303113305.
It is not a weakly prime, because it can be changed into another prime (1222303113131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611151556665 + 611151556666.
It is an arithmetic number, because the mean of its divisors is an integer number (611151556666).
Almost surely, 21222303113331 is an apocalyptic number.
1222303113331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222303113331 is an equidigital number, since it uses as much as digits as its factorization.
1222303113331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1222303113331 its reverse (1333113032221), we get a palindrome (2555416145552).
The spelling of 1222303113331 in words is "one trillion, two hundred twenty-two billion, three hundred three million, one hundred thirteen thousand, three hundred thirty-one".
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