Base | Representation |
---|---|
bin | 10001110010011100111… |
… | …101101111000011111011 |
3 | 11022212020110001102002211 |
4 | 101302130331233003323 |
5 | 130011440430010212 |
6 | 2333321551035551 |
7 | 154213212522166 |
oct | 21623475570373 |
9 | 4285213042084 |
10 | 1222404141307 |
11 | 4314672a7058 |
12 | 178ab080bbb7 |
13 | 8b37009b25b |
14 | 43243c2aadd |
15 | 21be6a499a7 |
hex | 11c9cf6f0fb |
1222404141307 has 2 divisors, whose sum is σ = 1222404141308. Its totient is φ = 1222404141306.
The previous prime is 1222404141251. The next prime is 1222404141331. The reversal of 1222404141307 is 7031414042221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1222404141307 - 235 = 1188044402939 is a prime.
It is not a weakly prime, because it can be changed into another prime (1222404145307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611202070653 + 611202070654.
It is an arithmetic number, because the mean of its divisors is an integer number (611202070654).
Almost surely, 21222404141307 is an apocalyptic number.
1222404141307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222404141307 is an equidigital number, since it uses as much as digits as its factorization.
1222404141307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10752, while the sum is 31.
Adding to 1222404141307 its reverse (7031414042221), we get a palindrome (8253818183528).
The spelling of 1222404141307 in words is "one trillion, two hundred twenty-two billion, four hundred four million, one hundred forty-one thousand, three hundred seven".
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