Base | Representation |
---|---|
bin | 1011000111100100011110… |
… | …1010000001111010100011 |
3 | 1121021200000220111012212022 |
4 | 2301321013222001322203 |
5 | 3100242120323442033 |
6 | 41555535015252055 |
7 | 2401126642035146 |
oct | 261710752017243 |
9 | 47250026435768 |
10 | 12224679124643 |
11 | 399350373a687 |
12 | 145528437a02b |
13 | 6a8a2291879b |
14 | 30396b59c05d |
15 | 162ed2cd3098 |
hex | b1e47a81ea3 |
12224679124643 has 2 divisors, whose sum is σ = 12224679124644. Its totient is φ = 12224679124642.
The previous prime is 12224679124631. The next prime is 12224679124673. The reversal of 12224679124643 is 34642197642221.
12224679124643 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12224679124643 - 236 = 12155959647907 is a prime.
It is not a weakly prime, because it can be changed into another prime (12224679124673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6112339562321 + 6112339562322.
It is an arithmetic number, because the mean of its divisors is an integer number (6112339562322).
Almost surely, 212224679124643 is an apocalyptic number.
12224679124643 is a deficient number, since it is larger than the sum of its proper divisors (1).
12224679124643 is an equidigital number, since it uses as much as digits as its factorization.
12224679124643 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6967296, while the sum is 53.
The spelling of 12224679124643 in words is "twelve trillion, two hundred twenty-four billion, six hundred seventy-nine million, one hundred twenty-four thousand, six hundred forty-three".
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