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122247813689 is a prime number
BaseRepresentation
bin111000111011010001…
…0011001101000111001
3102200112122211101012022
41301312202121220321
54000330420014224
6132054310524225
711555262162041
oct1616642315071
9380478741168
10122247813689
1147932781891
121b838666675
13b6b2ab9c41
145cb9aac721
1532a74b965e
hex1c76899a39

122247813689 has 2 divisors, whose sum is σ = 122247813690. Its totient is φ = 122247813688.

The previous prime is 122247813577. The next prime is 122247813731. The reversal of 122247813689 is 986318742221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75340917289 + 46906896400 = 274483^2 + 216580^2 .

It is an emirp because it is prime and its reverse (986318742221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 122247813689 - 228 = 121979378233 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 122247813689.

It is not a weakly prime, because it can be changed into another prime (122247813089) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61123906844 + 61123906845.

It is an arithmetic number, because the mean of its divisors is an integer number (61123906845).

Almost surely, 2122247813689 is an apocalyptic number.

It is an amenable number.

122247813689 is a deficient number, since it is larger than the sum of its proper divisors (1).

122247813689 is an equidigital number, since it uses as much as digits as its factorization.

122247813689 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2322432, while the sum is 53.

The spelling of 122247813689 in words is "one hundred twenty-two billion, two hundred forty-seven million, eight hundred thirteen thousand, six hundred eighty-nine".