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12227664913 is a prime number
BaseRepresentation
bin10110110001101001…
…10101110000010001
31011120011111201220021
423120310311300101
5200020240234123
65341201143441
7612004302562
oct133064656021
934504451807
1012227664913
11520521a6a2
12245302ab81
1311cb386ca9
1483dd62169
154b8741c5d
hex2d8d35c11

12227664913 has 2 divisors, whose sum is σ = 12227664914. Its totient is φ = 12227664912.

The previous prime is 12227664811. The next prime is 12227664931. The reversal of 12227664913 is 31946672221.

Together with next prime (12227664931) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9993401089 + 2234263824 = 99967^2 + 47268^2 .

It is a cyclic number.

It is not a de Polignac number, because 12227664913 - 217 = 12227533841 is a prime.

It is a super-2 number, since 2×122276649132 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12227664913.

It is not a weakly prime, because it can be changed into another prime (12227665913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6113832456 + 6113832457.

It is an arithmetic number, because the mean of its divisors is an integer number (6113832457).

Almost surely, 212227664913 is an apocalyptic number.

It is an amenable number.

12227664913 is a deficient number, since it is larger than the sum of its proper divisors (1).

12227664913 is an equidigital number, since it uses as much as digits as its factorization.

12227664913 is an evil number, because the sum of its binary digits is even.

The product of its digits is 217728, while the sum is 43.

The spelling of 12227664913 in words is "twelve billion, two hundred twenty-seven million, six hundred sixty-four thousand, nine hundred thirteen".