Base | Representation |
---|---|
bin | 111000111100110111… |
… | …0111100100100010011 |
3 | 102200200101201120121121 |
4 | 1301321232330210103 |
5 | 4000433131343011 |
6 | 132103504103111 |
7 | 11556513015622 |
oct | 1617156744423 |
9 | 380611646547 |
10 | 122301434131 |
11 | 4795aa756a8 |
12 | 1b852604a97 |
13 | b6c0c42206 |
14 | 5cc2c696b9 |
15 | 32ac05be71 |
hex | 1c79bbc913 |
122301434131 has 4 divisors (see below), whose sum is σ = 124903592352. Its totient is φ = 119699275912.
The previous prime is 122301434093. The next prime is 122301434141. The reversal of 122301434131 is 131434103221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 122301434131 - 215 = 122301401363 is a prime.
It is a super-2 number, since 2×1223014341312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 122301434096 and 122301434105.
It is not an unprimeable number, because it can be changed into a prime (122301434141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1301079040 + ... + 1301079133.
It is an arithmetic number, because the mean of its divisors is an integer number (31225898088).
Almost surely, 2122301434131 is an apocalyptic number.
122301434131 is a deficient number, since it is larger than the sum of its proper divisors (2602158221).
122301434131 is an equidigital number, since it uses as much as digits as its factorization.
122301434131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2602158220.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 122301434131 its reverse (131434103221), we get a palindrome (253735537352).
The spelling of 122301434131 in words is "one hundred twenty-two billion, three hundred one million, four hundred thirty-four thousand, one hundred thirty-one".
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