Base | Representation |
---|---|
bin | 111000111100111010… |
… | …1011011110110011011 |
3 | 102200200111220222221121 |
4 | 1301321311123312123 |
5 | 4000434100311011 |
6 | 132104004350111 |
7 | 11556533332042 |
oct | 1617165336633 |
9 | 380614828847 |
10 | 122303135131 |
11 | 47960a27691 |
12 | 1b8530a5337 |
13 | b6c13b9518 |
14 | 5cc318d559 |
15 | 32ac295e71 |
hex | 1c79d5bd9b |
122303135131 has 2 divisors, whose sum is σ = 122303135132. Its totient is φ = 122303135130.
The previous prime is 122303135083. The next prime is 122303135153. The reversal of 122303135131 is 131531303221.
It is a strong prime.
It is an emirp because it is prime and its reverse (131531303221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122303135131 - 29 = 122303134619 is a prime.
It is a super-2 number, since 2×1223031351312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 122303135096 and 122303135105.
It is not a weakly prime, because it can be changed into another prime (122303115131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61151567565 + 61151567566.
It is an arithmetic number, because the mean of its divisors is an integer number (61151567566).
Almost surely, 2122303135131 is an apocalyptic number.
122303135131 is a deficient number, since it is larger than the sum of its proper divisors (1).
122303135131 is an equidigital number, since it uses as much as digits as its factorization.
122303135131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 122303135131 its reverse (131531303221), we get a palindrome (253834438352).
The spelling of 122303135131 in words is "one hundred twenty-two billion, three hundred three million, one hundred thirty-five thousand, one hundred thirty-one".
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