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122311143105241 is a prime number
BaseRepresentation
bin11011110011110111001000…
…001111001010001011011001
3121001001211102212021022101011
4123303313020033022023121
5112012421210113331431
61112044544034253521
734522455101353066
oct3363671017121331
9531054385238334
10122311143105241
1135a76956702182
12118748764272a1
135332b78270b2c
14222bc68943c6d
15e218d81eccb1
hex6f3dc83ca2d9

122311143105241 has 2 divisors, whose sum is σ = 122311143105242. Its totient is φ = 122311143105240.

The previous prime is 122311143105191. The next prime is 122311143105299. The reversal of 122311143105241 is 142501341113221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118831037931225 + 3480105174016 = 10900965^2 + 1865504^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122311143105241 is a prime.

It is not a weakly prime, because it can be changed into another prime (122311143102241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61155571552620 + 61155571552621.

It is an arithmetic number, because the mean of its divisors is an integer number (61155571552621).

Almost surely, 2122311143105241 is an apocalyptic number.

It is an amenable number.

122311143105241 is a deficient number, since it is larger than the sum of its proper divisors (1).

122311143105241 is an equidigital number, since it uses as much as digits as its factorization.

122311143105241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 122311143105241 its reverse (142501341113221), we get a palindrome (264812484218462).

The spelling of 122311143105241 in words is "one hundred twenty-two trillion, three hundred eleven billion, one hundred forty-three million, one hundred five thousand, two hundred forty-one".