122312143405113 has 4 divisors (see below), whose sum is σ = 163082857873488. Its totient is φ = 81541428936740.

The previous prime is 122312143405031. The next prime is 122312143405117. The reversal of 122312143405113 is 311504341213221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 122312143405113 - 2¹⁶ = 122312143339577 is a prime.

It is a super-3 number, since 3×122312143405113³ (a number of 43 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (122312143405117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20385357234183 + ... + 20385357234188.

It is an arithmetic number, because the mean of its divisors is an integer number (40770714468372).

Almost surely, 2^{122312143405113} is an apocalyptic number.

It is an amenable number.

122312143405113 is a deficient number, since it is larger than the sum of its proper divisors (40770714468375).

122312143405113 is an equidigital number, since it uses as much as digits as its factorization.

122312143405113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40770714468374.

The product of its (nonzero) digits is 17280, while the sum is 33.

Adding to 122312143405113 its reverse (311504341213221), we get a palindrome (433816484618334).

The spelling of 122312143405113 in words is "one hundred twenty-two trillion, three hundred twelve billion, one hundred forty-three million, four hundred five thousand, one hundred thirteen".