Base | Representation |
---|---|
bin | 111000111101001011… |
… | …1110011010011110001 |
3 | 102200201010212200221121 |
4 | 1301322113303103301 |
5 | 4000443402102423 |
6 | 132104525422241 |
7 | 11560003033225 |
oct | 1617227632361 |
9 | 380633780847 |
10 | 122312144113 |
11 | 47966020225 |
12 | 1b85610a981 |
13 | b6c3221c93 |
14 | 5cc4456785 |
15 | 32ace7545d |
hex | 1c7a5f34f1 |
122312144113 has 2 divisors, whose sum is σ = 122312144114. Its totient is φ = 122312144112.
The previous prime is 122312144057. The next prime is 122312144117. The reversal of 122312144113 is 311441213221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 99658281969 + 22653862144 = 315687^2 + 150512^2 .
It is an emirp because it is prime and its reverse (311441213221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122312144113 - 217 = 122312013041 is a prime.
It is not a weakly prime, because it can be changed into another prime (122312144117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61156072056 + 61156072057.
It is an arithmetic number, because the mean of its divisors is an integer number (61156072057).
Almost surely, 2122312144113 is an apocalyptic number.
It is an amenable number.
122312144113 is a deficient number, since it is larger than the sum of its proper divisors (1).
122312144113 is an equidigital number, since it uses as much as digits as its factorization.
122312144113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1152, while the sum is 25.
Adding to 122312144113 its reverse (311441213221), we get a palindrome (433753357334).
The spelling of 122312144113 in words is "one hundred twenty-two billion, three hundred twelve million, one hundred forty-four thousand, one hundred thirteen".
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