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12231220321433 is a prime number
BaseRepresentation
bin1011000111111100110110…
…0010101101110010011001
31121022021220202220102222002
42301333031202231302121
53100344014400241213
642002540044010345
72401451020221551
oct261771542556231
947267822812862
1012231220321433
113996260005643
1214565aab309b5
136a9525b61b29
14303dcc208161
151632671c0658
hexb1fcd8adc99

12231220321433 has 2 divisors, whose sum is σ = 12231220321434. Its totient is φ = 12231220321432.

The previous prime is 12231220321291. The next prime is 12231220321451. The reversal of 12231220321433 is 33412302213221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11390712750169 + 840507571264 = 3375013^2 + 916792^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12231220321433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12231220321396 and 12231220321405.

It is not a weakly prime, because it can be changed into another prime (12231220320433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6115610160716 + 6115610160717.

It is an arithmetic number, because the mean of its divisors is an integer number (6115610160717).

Almost surely, 212231220321433 is an apocalyptic number.

It is an amenable number.

12231220321433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12231220321433 is an equidigital number, since it uses as much as digits as its factorization.

12231220321433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 12231220321433 its reverse (33412302213221), we get a palindrome (45643522534654).

The spelling of 12231220321433 in words is "twelve trillion, two hundred thirty-one billion, two hundred twenty million, three hundred twenty-one thousand, four hundred thirty-three".