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1223125153 = 4328444771
BaseRepresentation
bin100100011100111…
…0110100010100001
310011020112012021121
41020321312202201
510001110001103
6321211452241
742211251355
oct11071664241
93136465247
101223125153
11578471038
122a1757081
131665301c3
14b862d465
15725a76bd
hex48e768a1

1223125153 has 4 divisors (see below), whose sum is σ = 1251569968. Its totient is φ = 1194680340.

The previous prime is 1223125139. The next prime is 1223125193. The reversal of 1223125153 is 3515213221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1223125153 - 25 = 1223125121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1223125193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14222343 + ... + 14222428.

It is an arithmetic number, because the mean of its divisors is an integer number (312892492).

Almost surely, 21223125153 is an apocalyptic number.

It is an amenable number.

1223125153 is a deficient number, since it is larger than the sum of its proper divisors (28444815).

1223125153 is an equidigital number, since it uses as much as digits as its factorization.

1223125153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28444814.

The product of its digits is 1800, while the sum is 25.

The square root of 1223125153 is about 34973.2062156160. The cubic root of 1223125153 is about 1069.4413344135.

Adding to 1223125153 its reverse (3515213221), we get a palindrome (4738338374).

The spelling of 1223125153 in words is "one billion, two hundred twenty-three million, one hundred twenty-five thousand, one hundred fifty-three".

Divisors: 1 43 28444771 1223125153