Base | Representation |
---|---|
bin | 10001110011001101000… |
… | …000101001111010001001 |
3 | 11022221022121211002121000 |
4 | 101303031000221322021 |
5 | 130020113303304001 |
6 | 2333533544005213 |
7 | 154242201154350 |
oct | 21631500517211 |
9 | 4287277732530 |
10 | 1223210213001 |
11 | 431840304707 |
12 | 179096760809 |
13 | 8b46b09895a |
14 | 432bccd6997 |
15 | 21c426c0a86 |
hex | 11ccd029e89 |
1223210213001 has 16 divisors (see below), whose sum is σ = 2071043747200. Its totient is φ = 698977264464.
The previous prime is 1223210212981. The next prime is 1223210213009. The reversal of 1223210213001 is 1003120123221.
1223210213001 is a `hidden beast` number, since 1 + 22 + 321 + 0 + 21 + 300 + 1 = 666.
It is not a de Polignac number, because 1223210213001 - 214 = 1223210196617 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1223210213009) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3236005666 + ... + 3236006043.
It is an arithmetic number, because the mean of its divisors is an integer number (129440234200).
Almost surely, 21223210213001 is an apocalyptic number.
It is an amenable number.
1223210213001 is a deficient number, since it is larger than the sum of its proper divisors (847833534199).
1223210213001 is an equidigital number, since it uses as much as digits as its factorization.
1223210213001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6472011725 (or 6472011719 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 1223210213001 its reverse (1003120123221), we get a palindrome (2226330336222).
The spelling of 1223210213001 in words is "one trillion, two hundred twenty-three billion, two hundred ten million, two hundred thirteen thousand, one".
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