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122321102013001 is a prime number
BaseRepresentation
bin11011110100000000011001…
…110101011000001001001001
3121001002210010220201020112201
4123310000121311120021021
5112013102104103404001
61112053312152240201
734523256636600433
oct3364003165301111
9531083126636481
10122321102013001
1135a800a71aaa61
12118767956a0061
135333aa45a1568
14222c53144b653
15e21cbc690501
hex6f4019d58249

122321102013001 has 2 divisors, whose sum is σ = 122321102013002. Its totient is φ = 122321102013000.

The previous prime is 122321102012939. The next prime is 122321102013017. The reversal of 122321102013001 is 100310201123221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61210297337401 + 61110804675600 = 7823701^2 + 7817340^2 .

It is a cyclic number.

It is not a de Polignac number, because 122321102013001 - 27 = 122321102012873 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 122321102013001.

It is not a weakly prime, because it can be changed into another prime (122321102013041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61160551006500 + 61160551006501.

It is an arithmetic number, because the mean of its divisors is an integer number (61160551006501).

Almost surely, 2122321102013001 is an apocalyptic number.

It is an amenable number.

122321102013001 is a deficient number, since it is larger than the sum of its proper divisors (1).

122321102013001 is an equidigital number, since it uses as much as digits as its factorization.

122321102013001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 122321102013001 its reverse (100310201123221), we get a palindrome (222631303136222).

The spelling of 122321102013001 in words is "one hundred twenty-two trillion, three hundred twenty-one billion, one hundred two million, thirteen thousand, one".