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122325433 is a prime number
BaseRepresentation
bin1110100101010…
…00100110111001
322112011202221121
413102220212321
5222303403213
620045505241
73013514626
oct722504671
9275152847
10122325433
116305a9aa
1234b72221
131c45c519
141236334d
15ab1488d
hex74a89b9

122325433 has 2 divisors, whose sum is σ = 122325434. Its totient is φ = 122325432.

The previous prime is 122325397. The next prime is 122325457. The reversal of 122325433 is 334523221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106667584 + 15657849 = 10328^2 + 3957^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122325433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122325398 and 122325407.

It is not a weakly prime, because it can be changed into another prime (122325493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61162716 + 61162717.

It is an arithmetic number, because the mean of its divisors is an integer number (61162717).

Almost surely, 2122325433 is an apocalyptic number.

It is an amenable number.

122325433 is a deficient number, since it is larger than the sum of its proper divisors (1).

122325433 is an equidigital number, since it uses as much as digits as its factorization.

122325433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4320, while the sum is 25.

The square root of 122325433 is about 11060.0828658740. The cubic root of 122325433 is about 496.4081699661.

Adding to 122325433 its reverse (334523221), we get a palindrome (456848654).

The spelling of 122325433 in words is "one hundred twenty-two million, three hundred twenty-five thousand, four hundred thirty-three".