Base | Representation |
---|---|
bin | 11011110100001000101100… |
… | …001100111011111010011011 |
3 | 121001010122010001001120110022 |
4 | 123310020230030323322123 |
5 | 112013223320012111212 |
6 | 1112101343133341055 |
7 | 34524023304315020 |
oct | 3364105414737233 |
9 | 531118101046408 |
10 | 122330000113307 |
11 | 35a83952a22468 |
12 | 1187845963778b |
13 | 5334891bc447c |
14 | 222cb370d9547 |
15 | e2213d93e772 |
hex | 6f422c33be9b |
122330000113307 has 4 divisors (see below), whose sum is σ = 139805714415216. Its totient is φ = 104854285811400.
The previous prime is 122330000113247. The next prime is 122330000113393. The reversal of 122330000113307 is 703311000033221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 122330000113307 - 228 = 122329731677851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (122330000113007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8737857150944 + ... + 8737857150957.
It is an arithmetic number, because the mean of its divisors is an integer number (34951428603804).
Almost surely, 2122330000113307 is an apocalyptic number.
122330000113307 is a deficient number, since it is larger than the sum of its proper divisors (17475714301909).
122330000113307 is an equidigital number, since it uses as much as digits as its factorization.
122330000113307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17475714301908.
The product of its (nonzero) digits is 2268, while the sum is 26.
Adding to 122330000113307 its reverse (703311000033221), we get a palindrome (825641000146528).
The spelling of 122330000113307 in words is "one hundred twenty-two trillion, three hundred thirty billion, one hundred thirteen thousand, three hundred seven".
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