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122330041441537 is a prime number
BaseRepresentation
bin11011110100001000101110…
…101010100101110100000001
3121001010122012220211021010111
4123310020232222211310001
5112013223411102112122
61112101351211231321
734524024315514336
oct3364105652456401
9531118186737114
10122330041441537
1135a8397428aa26
121187846b448541
13533489a634747
14222cb3c7b698d
15e221423a4d77
hex6f422eaa5d01

122330041441537 has 2 divisors, whose sum is σ = 122330041441538. Its totient is φ = 122330041441536.

The previous prime is 122330041441501. The next prime is 122330041441561. The reversal of 122330041441537 is 735144140033221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66813474950401 + 55516566491136 = 8173951^2 + 7450944^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122330041441537 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 122330041441537.

It is not a weakly prime, because it can be changed into another prime (122330041441837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61165020720768 + 61165020720769.

It is an arithmetic number, because the mean of its divisors is an integer number (61165020720769).

Almost surely, 2122330041441537 is an apocalyptic number.

It is an amenable number.

122330041441537 is a deficient number, since it is larger than the sum of its proper divisors (1).

122330041441537 is an equidigital number, since it uses as much as digits as its factorization.

122330041441537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 241920, while the sum is 40.

Adding to 122330041441537 its reverse (735144140033221), we get a palindrome (857474181474758).

The spelling of 122330041441537 in words is "one hundred twenty-two trillion, three hundred thirty billion, forty-one million, four hundred forty-one thousand, five hundred thirty-seven".