Base | Representation |
---|---|
bin | 11011110100001000111001… |
… | …010100001010110100001001 |
3 | 121001010122200101000201112001 |
4 | 123310020321110022310021 |
5 | 112013224242322110121 |
6 | 1112101421032551001 |
7 | 34524031615301014 |
oct | 3364107124126411 |
9 | 531118611021461 |
10 | 122330220113161 |
11 | 35a83a56125625 |
12 | 118784bb252461 |
13 | 53348c8661ab8 |
14 | 222cb5840637b |
15 | e22152de9991 |
hex | 6f423950ad09 |
122330220113161 has 2 divisors, whose sum is σ = 122330220113162. Its totient is φ = 122330220113160.
The previous prime is 122330220113071. The next prime is 122330220113197. The reversal of 122330220113161 is 161311022033221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79551504297225 + 42778715815936 = 8919165^2 + 6540544^2 .
It is a cyclic number.
It is not a de Polignac number, because 122330220113161 - 245 = 87145848024329 is a prime.
It is not a weakly prime, because it can be changed into another prime (122330220116161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61165110056580 + 61165110056581.
It is an arithmetic number, because the mean of its divisors is an integer number (61165110056581).
Almost surely, 2122330220113161 is an apocalyptic number.
It is an amenable number.
122330220113161 is a deficient number, since it is larger than the sum of its proper divisors (1).
122330220113161 is an equidigital number, since it uses as much as digits as its factorization.
122330220113161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 122330220113161 its reverse (161311022033221), we get a palindrome (283641242146382).
The spelling of 122330220113161 in words is "one hundred twenty-two trillion, three hundred thirty billion, two hundred twenty million, one hundred thirteen thousand, one hundred sixty-one".
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