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12233031301307 is a prime number
BaseRepresentation
bin1011001000000011100101…
…1111000011100010111011
31121022110120222120202022202
42302000321133003202323
53100411222003120212
642003435455340415
72401543630256345
oct262007137034273
947273528522282
1012233031301307
113996aaa289623
121456a1552170b
136a97540c775b
1430412093c295
151633211970c2
hexb20397c38bb

12233031301307 has 2 divisors, whose sum is σ = 12233031301308. Its totient is φ = 12233031301306.

The previous prime is 12233031301277. The next prime is 12233031301339. The reversal of 12233031301307 is 70310313033221.

12233031301307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12233031301307 - 216 = 12233031235771 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12233031301307.

It is not a weakly prime, because it can be changed into another prime (12233031301207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6116515650653 + 6116515650654.

It is an arithmetic number, because the mean of its divisors is an integer number (6116515650654).

Almost surely, 212233031301307 is an apocalyptic number.

12233031301307 is a deficient number, since it is larger than the sum of its proper divisors (1).

12233031301307 is an equidigital number, since it uses as much as digits as its factorization.

12233031301307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6804, while the sum is 29.

Adding to 12233031301307 its reverse (70310313033221), we get a palindrome (82543344334528).

The spelling of 12233031301307 in words is "twelve trillion, two hundred thirty-three billion, thirty-one million, three hundred one thousand, three hundred seven".