Base | Representation |
---|---|
bin | 11011110100001001110101… |
… | …000101111000010101110011 |
3 | 121001010202021021010200020011 |
4 | 123310021311011320111303 |
5 | 112013233321042003220 |
6 | 1112102104340155351 |
7 | 34524065513555431 |
oct | 3364116505702563 |
9 | 531122237120204 |
10 | 122331223000435 |
11 | 35a84420240689 |
12 | 1187873b098b57 |
13 | 5334a28370217 |
14 | 222cc116a5d51 |
15 | e221b0e9b65a |
hex | 6f4275178573 |
122331223000435 has 32 divisors (see below), whose sum is σ = 151679177330688. Its totient is φ = 94616624568960.
The previous prime is 122331223000429. The next prime is 122331223000453. The reversal of 122331223000435 is 534000322133221.
It is not a de Polignac number, because 122331223000435 - 213 = 122331222992243 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 122331223000397 and 122331223000406.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1390036144 + ... + 1390124146.
It is an arithmetic number, because the mean of its divisors is an integer number (4739974291584).
Almost surely, 2122331223000435 is an apocalyptic number.
122331223000435 is a deficient number, since it is larger than the sum of its proper divisors (29347954330253).
122331223000435 is a wasteful number, since it uses less digits than its factorization.
122331223000435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96595.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 122331223000435 its reverse (534000322133221), we get a palindrome (656331545133656).
The spelling of 122331223000435 in words is "one hundred twenty-two trillion, three hundred thirty-one billion, two hundred twenty-three million, four hundred thirty-five", and thus it is an aban number.
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