Base | Representation |
---|---|
bin | 1011001000000100001110… |
… | …1010101000111101101001 |
3 | 1121022111000212222202020020 |
4 | 2302001003222220331221 |
5 | 3100412044220012223 |
6 | 42003504440351053 |
7 | 2401551103154652 |
oct | 262010352507551 |
9 | 47274025882206 |
10 | 12233202110313 |
11 | 3997087743998 |
12 | 1456a62775489 |
13 | 6a9780601082 |
14 | 3041394c2529 |
15 | 1633311871e3 |
hex | b2043aa8f69 |
12233202110313 has 4 divisors (see below), whose sum is σ = 16310936147088. Its totient is φ = 8155468073540.
The previous prime is 12233202110299. The next prime is 12233202110359. The reversal of 12233202110313 is 31301120233221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12233202110313 - 241 = 10034178854761 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12233202110713) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2038867018383 + ... + 2038867018388.
It is an arithmetic number, because the mean of its divisors is an integer number (4077734036772).
Almost surely, 212233202110313 is an apocalyptic number.
It is an amenable number.
12233202110313 is a deficient number, since it is larger than the sum of its proper divisors (4077734036775).
12233202110313 is an equidigital number, since it uses as much as digits as its factorization.
12233202110313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4077734036774.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 12233202110313 its reverse (31301120233221), we get a palindrome (43534322343534).
The spelling of 12233202110313 in words is "twelve trillion, two hundred thirty-three billion, two hundred two million, one hundred ten thousand, three hundred thirteen".
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