Base | Representation |
---|---|
bin | 111000111110010110… |
… | …0000100000101000001 |
3 | 102200210212000022002002 |
4 | 1301330230010011001 |
5 | 4001033324310423 |
6 | 132112434433345 |
7 | 11560654266203 |
oct | 1617454040501 |
9 | 380725008062 |
10 | 122351010113 |
11 | 47985a56892 |
12 | 1b867132855 |
13 | b6cb2ac607 |
14 | 5cc9692773 |
15 | 32b15a1228 |
hex | 1c7cb04141 |
122351010113 has 2 divisors, whose sum is σ = 122351010114. Its totient is φ = 122351010112.
The previous prime is 122351010091. The next prime is 122351010143. The reversal of 122351010113 is 311010153221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80206204849 + 42144805264 = 283207^2 + 205292^2 .
It is an emirp because it is prime and its reverse (311010153221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122351010113 - 226 = 122283901249 is a prime.
It is not a weakly prime, because it can be changed into another prime (122351010143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61175505056 + 61175505057.
It is an arithmetic number, because the mean of its divisors is an integer number (61175505057).
Almost surely, 2122351010113 is an apocalyptic number.
It is an amenable number.
122351010113 is a deficient number, since it is larger than the sum of its proper divisors (1).
122351010113 is an equidigital number, since it uses as much as digits as its factorization.
122351010113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 122351010113 its reverse (311010153221), we get a palindrome (433361163334).
The spelling of 122351010113 in words is "one hundred twenty-two billion, three hundred fifty-one million, ten thousand, one hundred thirteen".
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