Base | Representation |
---|---|
bin | 1011001000001100110111… |
… | …1000111101101100101011 |
3 | 1121022201000111121200221102 |
4 | 2302003031320331230223 |
5 | 3100431321401333232 |
6 | 42004530521032015 |
7 | 2401662422345156 |
oct | 262031570755453 |
9 | 47281014550842 |
10 | 12235521121067 |
11 | 399806776a002 |
12 | 14573ab32560b |
13 | 6a9a5cba129a |
14 | 3042b949cc9d |
15 | 163419a61662 |
hex | b20cde3db2b |
12235521121067 has 2 divisors, whose sum is σ = 12235521121068. Its totient is φ = 12235521121066.
The previous prime is 12235521121003. The next prime is 12235521121079. The reversal of 12235521121067 is 76012112553221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12235521121067 - 26 = 12235521121003 is a prime.
It is a super-3 number, since 3×122355211210673 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12235521121067.
It is not a weakly prime, because it can be changed into another prime (12235521126067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6117760560533 + 6117760560534.
It is an arithmetic number, because the mean of its divisors is an integer number (6117760560534).
Almost surely, 212235521121067 is an apocalyptic number.
12235521121067 is a deficient number, since it is larger than the sum of its proper divisors (1).
12235521121067 is an equidigital number, since it uses as much as digits as its factorization.
12235521121067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 38.
Adding to 12235521121067 its reverse (76012112553221), we get a palindrome (88247633674288).
The spelling of 12235521121067 in words is "twelve trillion, two hundred thirty-five billion, five hundred twenty-one million, one hundred twenty-one thousand, sixty-seven".
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