Base | Representation |
---|---|
bin | 11011110101001010000000… |
… | …111111011000101110011011 |
3 | 121001101100011100120202101021 |
4 | 123311022000333120232123 |
5 | 112020400442334221103 |
6 | 1112153503215503311 |
7 | 34532055424345105 |
oct | 3365120077305633 |
9 | 531340140522337 |
10 | 122400142101403 |
11 | 36000677284271 |
12 | 11889b73b27b37 |
13 | 533b38c89403a |
14 | 22322ac912575 |
15 | e23d9674abbd |
hex | 6f5280fd8b9b |
122400142101403 has 8 divisors (see below), whose sum is σ = 122466790818288. Its totient is φ = 122333511166464.
The previous prime is 122400142101389. The next prime is 122400142101451. The reversal of 122400142101403 is 304101241004221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 122400142101403 - 221 = 122400140004251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (122400142171403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9336675 + ... + 18220147.
It is an arithmetic number, because the mean of its divisors is an integer number (15308348852286).
Almost surely, 2122400142101403 is an apocalyptic number.
122400142101403 is a deficient number, since it is larger than the sum of its proper divisors (66648716885).
122400142101403 is an equidigital number, since it uses as much as digits as its factorization.
122400142101403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8890973.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 122400142101403 its reverse (304101241004221), we get a palindrome (426501383105624).
The spelling of 122400142101403 in words is "one hundred twenty-two trillion, four hundred billion, one hundred forty-two million, one hundred one thousand, four hundred three".
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