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122401025430457 is a prime number
BaseRepresentation
bin11011110101001010110101…
…101001000001001110111001
3121001101102102220201112001011
4123311022311221001032321
5112020404300002233312
61112154131012353521
734532116341461344
oct3365126551011671
9531342386645034
10122401025430457
1136000a8a95a484
121188a17b9158a1
13533b4a08a1657
142232353d6d45b
15e23de9082da7
hex6f52b5a413b9

122401025430457 has 2 divisors, whose sum is σ = 122401025430458. Its totient is φ = 122401025430456.

The previous prime is 122401025430413. The next prime is 122401025430527. The reversal of 122401025430457 is 754034520104221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84028315556416 + 38372709874041 = 9166696^2 + 6194571^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122401025430457 is a prime.

It is a super-2 number, since 2×1224010254304572 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (122401025431457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61200512715228 + 61200512715229.

It is an arithmetic number, because the mean of its divisors is an integer number (61200512715229).

Almost surely, 2122401025430457 is an apocalyptic number.

It is an amenable number.

122401025430457 is a deficient number, since it is larger than the sum of its proper divisors (1).

122401025430457 is an equidigital number, since it uses as much as digits as its factorization.

122401025430457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 268800, while the sum is 40.

Adding to 122401025430457 its reverse (754034520104221), we get a palindrome (876435545534678).

The spelling of 122401025430457 in words is "one hundred twenty-two trillion, four hundred one billion, twenty-five million, four hundred thirty thousand, four hundred fifty-seven".