Base | Representation |
---|---|
bin | 10110110011001000… |
… | …11001010000101011 |
3 | 1011121000222002022110 |
4 | 23121210121100223 |
5 | 200031433143430 |
6 | 5342324253403 |
7 | 612215253312 |
oct | 133144312053 |
9 | 34530862273 |
10 | 12240131115 |
11 | 5211264743 |
12 | 2457241263 |
13 | 1200b30244 |
14 | 841889279 |
15 | 4b98a57b0 |
hex | 2d991942b |
12240131115 has 16 divisors (see below), whose sum is σ = 19607853600. Its totient is φ = 6520188672.
The previous prime is 12240131093. The next prime is 12240131131. The reversal of 12240131115 is 51113104221.
It is not a de Polignac number, because 12240131115 - 26 = 12240131051 is a prime.
It is a super-2 number, since 2×122401311152 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12240131091 and 12240131100.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 479730 + ... + 504599.
It is an arithmetic number, because the mean of its divisors is an integer number (1225490850).
Almost surely, 212240131115 is an apocalyptic number.
12240131115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12240131115 is a deficient number, since it is larger than the sum of its proper divisors (7367722485).
12240131115 is an equidigital number, since it uses as much as digits as its factorization.
12240131115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 985166.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 12240131115 its reverse (51113104221), we get a palindrome (63353235336).
The spelling of 12240131115 in words is "twelve billion, two hundred forty million, one hundred thirty-one thousand, one hundred fifteen".
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