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12240131115 = 35829984329
BaseRepresentation
bin10110110011001000…
…11001010000101011
31011121000222002022110
423121210121100223
5200031433143430
65342324253403
7612215253312
oct133144312053
934530862273
1012240131115
115211264743
122457241263
131200b30244
14841889279
154b98a57b0
hex2d991942b

12240131115 has 16 divisors (see below), whose sum is σ = 19607853600. Its totient is φ = 6520188672.

The previous prime is 12240131093. The next prime is 12240131131. The reversal of 12240131115 is 51113104221.

It is not a de Polignac number, because 12240131115 - 26 = 12240131051 is a prime.

It is a super-2 number, since 2×122401311152 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12240131091 and 12240131100.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 479730 + ... + 504599.

It is an arithmetic number, because the mean of its divisors is an integer number (1225490850).

Almost surely, 212240131115 is an apocalyptic number.

12240131115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12240131115 is a deficient number, since it is larger than the sum of its proper divisors (7367722485).

12240131115 is an equidigital number, since it uses as much as digits as its factorization.

12240131115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 985166.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 12240131115 its reverse (51113104221), we get a palindrome (63353235336).

The spelling of 12240131115 in words is "twelve billion, two hundred forty million, one hundred thirty-one thousand, one hundred fifteen".

Divisors: 1 3 5 15 829 2487 4145 12435 984329 2952987 4921645 14764935 816008741 2448026223 4080043705 12240131115