Base | Representation |
---|---|
bin | 11011110101001101101000… |
… | …011100011100010001111001 |
3 | 121001101201011222102101202002 |
4 | 123311031220130130101321 |
5 | 112020431420431130113 |
6 | 1112155344413150345 |
7 | 34532253565533524 |
oct | 3365155034342171 |
9 | 531351158371662 |
10 | 122404025255033 |
11 | 3600228a210045 |
12 | 1188a87848b3b5 |
13 | 533b85b224092 |
14 | 223255a52bbbb |
15 | e240225dec58 |
hex | 6f536871c479 |
122404025255033 has 2 divisors, whose sum is σ = 122404025255034. Its totient is φ = 122404025255032.
The previous prime is 122404025255011. The next prime is 122404025255089. The reversal of 122404025255033 is 330552520404221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 117835084804969 + 4568940450064 = 10855187^2 + 2137508^2 .
It is a cyclic number.
It is not a de Polignac number, because 122404025255033 - 216 = 122404025189497 is a prime.
It is not a weakly prime, because it can be changed into another prime (122404025255093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61202012627516 + 61202012627517.
It is an arithmetic number, because the mean of its divisors is an integer number (61202012627517).
Almost surely, 2122404025255033 is an apocalyptic number.
It is an amenable number.
122404025255033 is a deficient number, since it is larger than the sum of its proper divisors (1).
122404025255033 is an equidigital number, since it uses as much as digits as its factorization.
122404025255033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288000, while the sum is 38.
Adding to 122404025255033 its reverse (330552520404221), we get a palindrome (452956545659254).
The spelling of 122404025255033 in words is "one hundred twenty-two trillion, four hundred four billion, twenty-five million, two hundred fifty-five thousand, thirty-three".
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