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12241040443 = 471511724819
BaseRepresentation
bin10110110011001111…
…10111010000111011
31011121002200021200021
423121213313100323
5200032201243233
65342355551311
7612226061362
oct133147672073
934532607607
1012241040443
115211825955
1224575bb537
13120108b0c8
14841a447d9
154b99d4e2d
hex2d99f743b

12241040443 has 8 divisors (see below), whose sum is σ = 12584286720. Its totient is φ = 11901244200.

The previous prime is 12241040419. The next prime is 12241040477. The reversal of 12241040443 is 34404014221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12241040443 - 25 = 12241040411 is a prime.

It is a super-2 number, since 2×122410404432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12241040543) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 855313 + ... + 869506.

It is an arithmetic number, because the mean of its divisors is an integer number (1573035840).

Almost surely, 212241040443 is an apocalyptic number.

12241040443 is a deficient number, since it is larger than the sum of its proper divisors (343246277).

12241040443 is a wasteful number, since it uses less digits than its factorization.

12241040443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1725017.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 12241040443 its reverse (34404014221), we get a palindrome (46645054664).

The spelling of 12241040443 in words is "twelve billion, two hundred forty-one million, forty thousand, four hundred forty-three".

Divisors: 1 47 151 7097 1724819 81066493 260447669 12241040443