Base | Representation |
---|---|
bin | 10110110011010001… |
… | …11010000011010011 |
3 | 1011121010012011221010 |
4 | 23121220322003103 |
5 | 200032234022003 |
6 | 5342405502003 |
7 | 612231311052 |
oct | 133150720323 |
9 | 34533164833 |
10 | 12241314003 |
11 | 52119a2436 |
12 | 2457711903 |
13 | 1201155789 |
14 | 841ab6399 |
15 | 4b9a3b003 |
hex | 2d9a3a0d3 |
12241314003 has 16 divisors (see below), whose sum is σ = 16704786560. Its totient is φ = 7969437504.
The previous prime is 12241313999. The next prime is 12241314011. The reversal of 12241314003 is 30041314221.
12241314003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12241314003 - 22 = 12241313999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12241314103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1095975 + ... + 1107087.
It is an arithmetic number, because the mean of its divisors is an integer number (1044049160).
Almost surely, 212241314003 is an apocalyptic number.
12241314003 is a deficient number, since it is larger than the sum of its proper divisors (4463472557).
12241314003 is a wasteful number, since it uses less digits than its factorization.
12241314003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19698.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 12241314003 its reverse (30041314221), we get a palindrome (42282628224).
The spelling of 12241314003 in words is "twelve billion, two hundred forty-one million, three hundred fourteen thousand, three".
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