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1224140113 = 7199204061
BaseRepresentation
bin100100011110110…
…1110010101010001
310011022102202112201
41020331232111101
510001334440423
6321245323201
742223006420
oct11075562521
93138382481
101224140113
11578aa4649
122a1b66501
131667c7181
14b88152b7
15727082ad
hex48f6e551

1224140113 has 8 divisors (see below), whose sum is σ = 1472649920. Its totient is φ = 994038480.

The previous prime is 1224140101. The next prime is 1224140117. The reversal of 1224140113 is 3110414221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1224140113 - 25 = 1224140081 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (19).

It is not an unprimeable number, because it can be changed into a prime (1224140117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4601898 + ... + 4602163.

It is an arithmetic number, because the mean of its divisors is an integer number (184081240).

Almost surely, 21224140113 is an apocalyptic number.

It is an amenable number.

1224140113 is a deficient number, since it is larger than the sum of its proper divisors (248509807).

1224140113 is an equidigital number, since it uses as much as digits as its factorization.

1224140113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9204087.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 1224140113 is about 34987.7137435415. The cubic root of 1224140113 is about 1069.7370632348.

Adding to 1224140113 its reverse (3110414221), we get a palindrome (4334554334).

The spelling of 1224140113 in words is "one billion, two hundred twenty-four million, one hundred forty thousand, one hundred thirteen".

Divisors: 1 7 19 133 9204061 64428427 174877159 1224140113