Base | Representation |
---|---|
bin | 11011110101011100100010… |
… | …000111110010000001010010 |
3 | 121001110020111001100001111202 |
4 | 123311130202013302001102 |
5 | 112021212202434144442 |
6 | 1112210552213511202 |
7 | 34533361230644201 |
oct | 3365344207620122 |
9 | 531406431301452 |
10 | 122420025303122 |
11 | 3600904a888a88 |
12 | 118919a2942502 |
13 | 534020acc6161 |
14 | 22332374b3238 |
15 | e2465c0e4c32 |
hex | 6f57221f2052 |
122420025303122 has 4 divisors (see below), whose sum is σ = 183630037954686. Its totient is φ = 61210012651560.
The previous prime is 122420025303109. The next prime is 122420025303137. The reversal of 122420025303122 is 221303520024221.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 97478281325881 + 24941743977241 = 9873109^2 + 4994171^2 .
It is a super-4 number, since 4×1224200253031224 (a number of 57 digits) contains 4444 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30605006325779 + ... + 30605006325782.
Almost surely, 2122420025303122 is an apocalyptic number.
122420025303122 is a deficient number, since it is larger than the sum of its proper divisors (61210012651564).
122420025303122 is an equidigital number, since it uses as much as digits as its factorization.
122420025303122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61210012651563.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 122420025303122 its reverse (221303520024221), we get a palindrome (343723545327343).
The spelling of 122420025303122 in words is "one hundred twenty-two trillion, four hundred twenty billion, twenty-five million, three hundred three thousand, one hundred twenty-two".
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