12242324000041 has 4 divisors (see below), whose sum is σ = 12242639994192. Its totient is φ = 12242008005892.

The previous prime is 12242324000017. The next prime is 12242324000083. The reversal of 12242324000041 is 14000042324221.

12242324000041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12242324000041 - 2¹⁵ = 12242323967273 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12242324000141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157938955 + ... + 158016448.

It is an arithmetic number, because the mean of its divisors is an integer number (3060659998548).

Almost surely, 2^{12242324000041} is an apocalyptic number.

It is an amenable number.

12242324000041 is a deficient number, since it is larger than the sum of its proper divisors (315994151).

12242324000041 is an equidigital number, since it uses as much as digits as its factorization.

12242324000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 315994150.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 12242324000041 its reverse (14000042324221), we get a palindrome (26242366324262).

The spelling of 12242324000041 in words is "twelve trillion, two hundred forty-two billion, three hundred twenty-four million, forty-one", and thus it is an aban number.