Base | Representation |
---|---|
bin | 111001000000110100… |
… | …1100001110000100011 |
3 | 102201000122121101010102 |
4 | 1302001221201300203 |
5 | 4001221130400311 |
6 | 132125010253015 |
7 | 11563014536516 |
oct | 1620151416043 |
9 | 381018541112 |
10 | 122434231331 |
11 | 47a18a28155 |
12 | 1b88ab8716b |
13 | b7125c9c39 |
14 | 5cd6756d7d |
15 | 32b8a3e43b |
hex | 1c81a61c23 |
122434231331 has 2 divisors, whose sum is σ = 122434231332. Its totient is φ = 122434231330.
The previous prime is 122434231321. The next prime is 122434231393. The reversal of 122434231331 is 133132434221.
It is a weak prime.
It is an emirp because it is prime and its reverse (133132434221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122434231331 - 26 = 122434231267 is a prime.
It is a super-2 number, since 2×1224342313312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 122434231294 and 122434231303.
It is not a weakly prime, because it can be changed into another prime (122434231321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61217115665 + 61217115666.
It is an arithmetic number, because the mean of its divisors is an integer number (61217115666).
Almost surely, 2122434231331 is an apocalyptic number.
122434231331 is a deficient number, since it is larger than the sum of its proper divisors (1).
122434231331 is an equidigital number, since it uses as much as digits as its factorization.
122434231331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10368, while the sum is 29.
Adding to 122434231331 its reverse (133132434221), we get a palindrome (255566665552).
The spelling of 122434231331 in words is "one hundred twenty-two billion, four hundred thirty-four million, two hundred thirty-one thousand, three hundred thirty-one".
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