Base | Representation |
---|---|
bin | 1011001000101010010110… |
… | …0011100000111010101111 |
3 | 1121100110102222202002020101 |
4 | 2302022211203200322233 |
5 | 3101044023143002421 |
6 | 42012320040531531 |
7 | 2402362500545245 |
oct | 262124543407257 |
9 | 47313388662211 |
10 | 12243434344111 |
11 | 39a0458557663 |
12 | 1458a39480ba7 |
13 | 6aa721450499 |
14 | 30482a418795 |
15 | 16372e61a191 |
hex | b22a58e0eaf |
12243434344111 has 16 divisors (see below), whose sum is σ = 13119038000640. Its totient is φ = 11392194270240.
The previous prime is 12243434344007. The next prime is 12243434344159. The reversal of 12243434344111 is 11144343434221.
12243434344111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 12243434344111 - 213 = 12243434335919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12243434344181) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16899840 + ... + 17609413.
It is an arithmetic number, because the mean of its divisors is an integer number (819939875040).
Almost surely, 212243434344111 is an apocalyptic number.
12243434344111 is a deficient number, since it is larger than the sum of its proper divisors (875603656529).
12243434344111 is a wasteful number, since it uses less digits than its factorization.
12243434344111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34509606.
The product of its digits is 110592, while the sum is 37.
Adding to 12243434344111 its reverse (11144343434221), we get a palindrome (23387777778332).
The spelling of 12243434344111 in words is "twelve trillion, two hundred forty-three billion, four hundred thirty-four million, three hundred forty-four thousand, one hundred eleven".
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