Base | Representation |
---|---|
bin | 11011110101101111100001… |
… | …001010111000101010110011 |
3 | 121001112012002201120000022111 |
4 | 123311233201022320222303 |
5 | 112022030430032343402 |
6 | 1112224203101550151 |
7 | 34535012340464254 |
oct | 3365574112705263 |
9 | 531465081500274 |
10 | 122440410434227 |
11 | 36016760747776 |
12 | 11895931875357 |
13 | 5342109407602 |
14 | 223420c9acb2b |
15 | e24e51a889d7 |
hex | 6f5be12b8ab3 |
122440410434227 has 2 divisors, whose sum is σ = 122440410434228. Its totient is φ = 122440410434226.
The previous prime is 122440410434219. The next prime is 122440410434233. The reversal of 122440410434227 is 722434014044221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122440410434227 - 23 = 122440410434219 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 122440410434227.
It is not a weakly prime, because it can be changed into another prime (122440410434327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61220205217113 + 61220205217114.
It is an arithmetic number, because the mean of its divisors is an integer number (61220205217114).
Almost surely, 2122440410434227 is an apocalyptic number.
122440410434227 is a deficient number, since it is larger than the sum of its proper divisors (1).
122440410434227 is an equidigital number, since it uses as much as digits as its factorization.
122440410434227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 344064, while the sum is 40.
Adding to 122440410434227 its reverse (722434014044221), we get a palindrome (844874424478448).
The spelling of 122440410434227 in words is "one hundred twenty-two trillion, four hundred forty billion, four hundred ten million, four hundred thirty-four thousand, two hundred twenty-seven".
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