Base | Representation |
---|---|
bin | 10110110100000001… |
… | …00101001011111001 |
3 | 1011121112212110221121 |
4 | 23122000211023321 |
5 | 200040331114433 |
6 | 5343150505241 |
7 | 612335126242 |
oct | 133200451371 |
9 | 34545773847 |
10 | 12247519993 |
11 | 5215451055 |
12 | 2459805221 |
13 | 1202519467 |
14 | 84284dcc9 |
15 | 4ba364c2d |
hex | 2da0252f9 |
12247519993 has 2 divisors, whose sum is σ = 12247519994. Its totient is φ = 12247519992.
The previous prime is 12247519939. The next prime is 12247520003. The reversal of 12247519993 is 39991574221.
Together with previous prime (12247519939) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7490383209 + 4757136784 = 86547^2 + 68972^2 .
It is an emirp because it is prime and its reverse (39991574221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12247519993 - 229 = 11710649081 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12247519993.
It is not a weakly prime, because it can be changed into another prime (12247519913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6123759996 + 6123759997.
It is an arithmetic number, because the mean of its divisors is an integer number (6123759997).
Almost surely, 212247519993 is an apocalyptic number.
It is an amenable number.
12247519993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12247519993 is an equidigital number, since it uses as much as digits as its factorization.
12247519993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1224720, while the sum is 52.
The spelling of 12247519993 in words is "twelve billion, two hundred forty-seven million, five hundred nineteen thousand, nine hundred ninety-three".
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