Base | Representation |
---|---|
bin | 1011001001000111110110… |
… | …0000111000100000001010 |
3 | 1121101012212211011002102222 |
4 | 2302101331200320200022 |
5 | 3101211232220001414 |
6 | 42020105454254042 |
7 | 2403062636012441 |
oct | 262217540704012 |
9 | 47335784132388 |
10 | 12251352500234 |
11 | 39a3851104541 |
12 | 145a4891b7322 |
13 | 6ab3b3a38b73 |
14 | 304d7bc99d58 |
15 | 163a4484a68e |
hex | b247d83880a |
12251352500234 has 8 divisors (see below), whose sum is σ = 18377045285088. Its totient is φ = 6125670738540.
The previous prime is 12251352500221. The next prime is 12251352500249. The reversal of 12251352500234 is 43200525315221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 12251352500194 and 12251352500203.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1103939 + ... + 5071625.
It is an arithmetic number, because the mean of its divisors is an integer number (2297130660636).
Almost surely, 212251352500234 is an apocalyptic number.
12251352500234 is a deficient number, since it is larger than the sum of its proper divisors (6125692784854).
12251352500234 is a wasteful number, since it uses less digits than its factorization.
12251352500234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5511580.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 12251352500234 its reverse (43200525315221), we get a palindrome (55451877815455).
The spelling of 12251352500234 in words is "twelve trillion, two hundred fifty-one billion, three hundred fifty-two million, five hundred thousand, two hundred thirty-four".
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