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12251352500234 = 215438913967687
BaseRepresentation
bin1011001001000111110110…
…0000111000100000001010
31121101012212211011002102222
42302101331200320200022
53101211232220001414
642020105454254042
72403062636012441
oct262217540704012
947335784132388
1012251352500234
1139a3851104541
12145a4891b7322
136ab3b3a38b73
14304d7bc99d58
15163a4484a68e
hexb247d83880a

12251352500234 has 8 divisors (see below), whose sum is σ = 18377045285088. Its totient is φ = 6125670738540.

The previous prime is 12251352500221. The next prime is 12251352500249. The reversal of 12251352500234 is 43200525315221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12251352500194 and 12251352500203.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1103939 + ... + 5071625.

It is an arithmetic number, because the mean of its divisors is an integer number (2297130660636).

Almost surely, 212251352500234 is an apocalyptic number.

12251352500234 is a deficient number, since it is larger than the sum of its proper divisors (6125692784854).

12251352500234 is a wasteful number, since it uses less digits than its factorization.

12251352500234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5511580.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 12251352500234 its reverse (43200525315221), we get a palindrome (55451877815455).

The spelling of 12251352500234 in words is "twelve trillion, two hundred fifty-one billion, three hundred fifty-two million, five hundred thousand, two hundred thirty-four".

Divisors: 1 2 1543891 3087782 3967687 7935374 6125676250117 12251352500234