Base | Representation |
---|---|
bin | 10110110100100100… |
… | …10000100010110010 |
3 | 1011121212120220122202 |
4 | 23122102100202302 |
5 | 200043022412114 |
6 | 5343434103202 |
7 | 612422406461 |
oct | 133222204262 |
9 | 34555526582 |
10 | 12252154034 |
11 | 521802673a |
12 | 245b27ab02 |
13 | 120347c7b3 |
14 | 8432d89d8 |
15 | 4ba97ccde |
hex | 2da4908b2 |
12252154034 has 4 divisors (see below), whose sum is σ = 18378231054. Its totient is φ = 6126077016.
The previous prime is 12252154021. The next prime is 12252154037. The reversal of 12252154034 is 43045125221.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43045125221 = 7 ⋅6149303603.
It can be written as a sum of positive squares in only one way, i.e., 9967027225 + 2285126809 = 99835^2 + 47803^2 .
It is a super-3 number, since 3×122521540343 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12252153988 and 12252154006.
It is not an unprimeable number, because it can be changed into a prime (12252154037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3063038507 + ... + 3063038510.
Almost surely, 212252154034 is an apocalyptic number.
12252154034 is a deficient number, since it is larger than the sum of its proper divisors (6126077020).
12252154034 is an equidigital number, since it uses as much as digits as its factorization.
12252154034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6126077019.
The product of its (nonzero) digits is 9600, while the sum is 29.
Adding to 12252154034 its reverse (43045125221), we get a palindrome (55297279255).
The spelling of 12252154034 in words is "twelve billion, two hundred fifty-two million, one hundred fifty-four thousand, thirty-four".
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