Base | Representation |
---|---|
bin | 10001110101000101101… |
… | …110101011011111001011 |
3 | 11100010112202211120102122 |
4 | 101311011232223133023 |
5 | 130033240244402021 |
6 | 2334510533521455 |
7 | 154343323200443 |
oct | 21650556533713 |
9 | 4303482746378 |
10 | 1225235544011 |
11 | 43268a582896 |
12 | 179560aa328b |
13 | 8b701871a7b |
14 | 43431ca7123 |
15 | 21d103d8bab |
hex | 11d45bab7cb |
1225235544011 has 2 divisors, whose sum is σ = 1225235544012. Its totient is φ = 1225235544010.
The previous prime is 1225235543989. The next prime is 1225235544089. The reversal of 1225235544011 is 1104455325221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1225235544011 - 26 = 1225235543947 is a prime.
It is a super-3 number, since 3×12252355440113 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1225235544811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612617772005 + 612617772006.
It is an arithmetic number, because the mean of its divisors is an integer number (612617772006).
Almost surely, 21225235544011 is an apocalyptic number.
1225235544011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1225235544011 is an equidigital number, since it uses as much as digits as its factorization.
1225235544011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48000, while the sum is 35.
The spelling of 1225235544011 in words is "one trillion, two hundred twenty-five billion, two hundred thirty-five million, five hundred forty-four thousand, eleven".
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