Base | Representation |
---|---|
bin | 100100100000111… |
… | …1011010010011001 |
3 | 10011101111201201012 |
4 | 1021001323102121 |
5 | 10002130214003 |
6 | 321325103305 |
7 | 42235245251 |
oct | 11101732231 |
9 | 3141451635 |
10 | 1225241753 |
11 | 57968729a |
12 | 2a23b7b35 |
13 | 166ac1728 |
14 | b8a20961 |
15 | 728748d8 |
hex | 4907b499 |
1225241753 has 4 divisors (see below), whose sum is σ = 1237137408. Its totient is φ = 1213346100.
The previous prime is 1225241749. The next prime is 1225241761. The reversal of 1225241753 is 3571425221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1225241753 - 22 = 1225241749 is a prime.
It is a super-3 number, since 3×12252417533 (a number of 28 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1225241713) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5947673 + ... + 5947878.
It is an arithmetic number, because the mean of its divisors is an integer number (309284352).
Almost surely, 21225241753 is an apocalyptic number.
It is an amenable number.
1225241753 is a deficient number, since it is larger than the sum of its proper divisors (11895655).
1225241753 is a wasteful number, since it uses less digits than its factorization.
1225241753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11895654.
The product of its digits is 16800, while the sum is 32.
The square root of 1225241753 is about 35003.4534439104. The cubic root of 1225241753 is about 1070.0578630600.
Adding to 1225241753 its reverse (3571425221), we get a palindrome (4796666974).
The spelling of 1225241753 in words is "one billion, two hundred twenty-five million, two hundred forty-one thousand, seven hundred fifty-three".
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