Base | Representation |
---|---|
bin | 10110110100101010… |
… | …11111011011011001 |
3 | 1011121221011222001220 |
4 | 23122111133123121 |
5 | 200043232021213 |
6 | 5343504202253 |
7 | 612432536151 |
oct | 133225373331 |
9 | 34557158056 |
10 | 12253001433 |
11 | 5218555372 |
12 | 245b609389 |
13 | 12036b840a |
14 | 843479761 |
15 | 4baa98e23 |
hex | 2da55f6d9 |
12253001433 has 16 divisors (see below), whose sum is σ = 16488894336. Its totient is φ = 8092949760.
The previous prime is 12253001419. The next prime is 12253001443. The reversal of 12253001433 is 33410035221.
It is not a de Polignac number, because 12253001433 - 28 = 12253001177 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12253001443) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 982668 + ... + 995058.
It is an arithmetic number, because the mean of its divisors is an integer number (1030555896).
Almost surely, 212253001433 is an apocalyptic number.
It is an amenable number.
12253001433 is a deficient number, since it is larger than the sum of its proper divisors (4235892903).
12253001433 is a wasteful number, since it uses less digits than its factorization.
12253001433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15424.
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 12253001433 its reverse (33410035221), we get a palindrome (45663036654).
The spelling of 12253001433 in words is "twelve billion, two hundred fifty-three million, one thousand, four hundred thirty-three".
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