Base | Representation |
---|---|
bin | 10001110101010101100… |
… | …100000100111010101011 |
3 | 11100011020021201021222221 |
4 | 101311111210010322223 |
5 | 130034311301400133 |
6 | 2334553143454511 |
7 | 154353030220021 |
oct | 21652544047253 |
9 | 4304207637887 |
10 | 1225501200043 |
11 | 43280652a12a |
12 | 179615a57437 |
13 | 8b7449065a3 |
14 | 4345929a711 |
15 | 21d288b1a2d |
hex | 11d55904eab |
1225501200043 has 2 divisors, whose sum is σ = 1225501200044. Its totient is φ = 1225501200042.
The previous prime is 1225501199981. The next prime is 1225501200139. The reversal of 1225501200043 is 3400021055221.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1225501200043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1225501199990 and 1225501200017.
It is not a weakly prime, because it can be changed into another prime (1225501230043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612750600021 + 612750600022.
It is an arithmetic number, because the mean of its divisors is an integer number (612750600022).
Almost surely, 21225501200043 is an apocalyptic number.
1225501200043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1225501200043 is an equidigital number, since it uses as much as digits as its factorization.
1225501200043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 1225501200043 its reverse (3400021055221), we get a palindrome (4625522255264).
The spelling of 1225501200043 in words is "one trillion, two hundred twenty-five billion, five hundred one million, two hundred thousand, forty-three".
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