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122553434523041 is a prime number
BaseRepresentation
bin11011110111011000110001…
…111011100100010110100001
3121001220222211120022121122222
4123313120301323210112201
5112030403413214214131
61112352134240240425
734546123232416214
oct3367306173442641
9531828746277588
10122553434523041
113605a68a910535
12118b3815310115
13534c97c2a1282
14223989166977b
15e27d693d287b
hex6f7631ee45a1

122553434523041 has 2 divisors, whose sum is σ = 122553434523042. Its totient is φ = 122553434523040.

The previous prime is 122553434522971. The next prime is 122553434523097. The reversal of 122553434523041 is 140325434355221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115074965290000 + 7478469233041 = 10727300^2 + 2734679^2 .

It is a cyclic number.

It is not a de Polignac number, because 122553434523041 - 242 = 118155388011937 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122553434522983 and 122553434523001.

It is not a weakly prime, because it can be changed into another prime (122553434523941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61276717261520 + 61276717261521.

It is an arithmetic number, because the mean of its divisors is an integer number (61276717261521).

Almost surely, 2122553434523041 is an apocalyptic number.

It is an amenable number.

122553434523041 is a deficient number, since it is larger than the sum of its proper divisors (1).

122553434523041 is an equidigital number, since it uses as much as digits as its factorization.

122553434523041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728000, while the sum is 44.

Adding to 122553434523041 its reverse (140325434355221), we get a palindrome (262878868878262).

The spelling of 122553434523041 in words is "one hundred twenty-two trillion, five hundred fifty-three billion, four hundred thirty-four million, five hundred twenty-three thousand, forty-one".