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122555533141142 = 2199433711151213
BaseRepresentation
bin11011110111011010101111…
…000001001010010010010110
3121001221012020211020110111022
4123313122233001022102112
5112030422212441004032
61112353122405041142
734546226234366303
oct3367325701122226
9531835224213438
10122555533141142
1136060567495362
12118b41000b61b2
13534cc24cc712a
142239a102760aa
15e27e3d775512
hex6f76af04a496

122555533141142 has 16 divisors (see below), whose sum is σ = 185183776125600. Its totient is φ = 60829030069632.

The previous prime is 122555533141133. The next prime is 122555533141157. The reversal of 122555533141142 is 241141335555221.

It is a super-3 number, since 3×1225555331411423 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 122555533141093 and 122555533141102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 355403273 + ... + 355747940.

It is an arithmetic number, because the mean of its divisors is an integer number (11573986007850).

Almost surely, 2122555533141142 is an apocalyptic number.

122555533141142 is a deficient number, since it is larger than the sum of its proper divisors (62628242984458).

122555533141142 is a wasteful number, since it uses less digits than its factorization.

122555533141142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 711151847.

The product of its digits is 720000, while the sum is 44.

Adding to 122555533141142 its reverse (241141335555221), we get a palindrome (363696868696363).

The spelling of 122555533141142 in words is "one hundred twenty-two trillion, five hundred fifty-five billion, five hundred thirty-three million, one hundred forty-one thousand, one hundred forty-two".

Divisors: 1 2 199 398 433 866 86167 172334 711151213 1422302426 141519091387 283038182774 307928475229 615856950458 61277766570571 122555533141142