Base | Representation |
---|---|
bin | 11011110111011010101111… |
… | …000001001010010010010110 |
3 | 121001221012020211020110111022 |
4 | 123313122233001022102112 |
5 | 112030422212441004032 |
6 | 1112353122405041142 |
7 | 34546226234366303 |
oct | 3367325701122226 |
9 | 531835224213438 |
10 | 122555533141142 |
11 | 36060567495362 |
12 | 118b41000b61b2 |
13 | 534cc24cc712a |
14 | 2239a102760aa |
15 | e27e3d775512 |
hex | 6f76af04a496 |
122555533141142 has 16 divisors (see below), whose sum is σ = 185183776125600. Its totient is φ = 60829030069632.
The previous prime is 122555533141133. The next prime is 122555533141157. The reversal of 122555533141142 is 241141335555221.
It is a super-3 number, since 3×1225555331411423 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 122555533141093 and 122555533141102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 355403273 + ... + 355747940.
It is an arithmetic number, because the mean of its divisors is an integer number (11573986007850).
Almost surely, 2122555533141142 is an apocalyptic number.
122555533141142 is a deficient number, since it is larger than the sum of its proper divisors (62628242984458).
122555533141142 is a wasteful number, since it uses less digits than its factorization.
122555533141142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 711151847.
The product of its digits is 720000, while the sum is 44.
Adding to 122555533141142 its reverse (241141335555221), we get a palindrome (363696868696363).
The spelling of 122555533141142 in words is "one hundred twenty-two trillion, five hundred fifty-five billion, five hundred thirty-three million, one hundred forty-one thousand, one hundred forty-two".
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