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1226017131257 is a prime number
BaseRepresentation
bin10001110101110100010…
…100001100101011111001
311100012120020112022120102
4101311310110030223321
5130041340341200012
62335120254005145
7154401563445452
oct21656424145371
94305506468512
101226017131257
11432a50787966
1217973a7a67b5
138b7c7778b29
14434a79dc129
1521d58d252c2
hex11d7450caf9

1226017131257 has 2 divisors, whose sum is σ = 1226017131258. Its totient is φ = 1226017131256.

The previous prime is 1226017131223. The next prime is 1226017131263. The reversal of 1226017131257 is 7521317106221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 738630238096 + 487386893161 = 859436^2 + 698131^2 .

It is a cyclic number.

It is not a de Polignac number, because 1226017131257 - 224 = 1226000354041 is a prime.

It is a super-2 number, since 2×12260171312572 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1226017131257.

It is not a weakly prime, because it can be changed into another prime (1226017121257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 613008565628 + 613008565629.

It is an arithmetic number, because the mean of its divisors is an integer number (613008565629).

Almost surely, 21226017131257 is an apocalyptic number.

It is an amenable number.

1226017131257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1226017131257 is an equidigital number, since it uses as much as digits as its factorization.

1226017131257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 35280, while the sum is 38.

The spelling of 1226017131257 in words is "one trillion, two hundred twenty-six billion, seventeen million, one hundred thirty-one thousand, two hundred fifty-seven".