Base | Representation |
---|---|
bin | 10001110110100100110… |
… | …100100100111000011011 |
3 | 11100021122221211100011222 |
4 | 101312210310210320123 |
5 | 130100022204102324 |
6 | 2335333124242255 |
7 | 154431004543115 |
oct | 21664464447033 |
9 | 4307587740158 |
10 | 1226830925339 |
11 | 43332908a458 |
12 | 17992724038b |
13 | 8b8c724b4a6 |
14 | 43543b183b5 |
15 | 21da54c455e |
hex | 11da4d24e1b |
1226830925339 has 2 divisors, whose sum is σ = 1226830925340. Its totient is φ = 1226830925338.
The previous prime is 1226830925329. The next prime is 1226830925393. The reversal of 1226830925339 is 9335290386221.
Together with next prime (1226830925393) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1226830925339 - 28 = 1226830925083 is a prime.
It is a super-2 number, since 2×12268309253392 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1226830925329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 613415462669 + 613415462670.
It is an arithmetic number, because the mean of its divisors is an integer number (613415462670).
Almost surely, 21226830925339 is an apocalyptic number.
1226830925339 is a deficient number, since it is larger than the sum of its proper divisors (1).
1226830925339 is an equidigital number, since it uses as much as digits as its factorization.
1226830925339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4199040, while the sum is 53.
The spelling of 1226830925339 in words is "one trillion, two hundred twenty-six billion, eight hundred thirty million, nine hundred twenty-five thousand, three hundred thirty-nine".
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